New Release on Spotify.
Anyone checked it out yet?
Wait for official confirmation.
This looks like someone who has illegaly tagged Sapien Med as a co-release artist…
It is there here too must be official, Apple hates pirates ![]()
edit: checked the YT channel it is not there, not an official release I guess
This is exactly what seems to have happened. I don’t know how that works… Can you just claim you collab’d with someone and that’s it? Mustn’t the other party confirm it first?
But yes, this is not official as far as we know
Grrr. Why can’t people just leave Dream alone?
The extreme greed + perception of low risk, high reward.
A good lawsuit would change that.
You wouldn’t believe how cunning they often get just to claim “sapien”.
So many parasites
Because he’s too skilled ![]()
I put the Not Legit in the title, since we know there are people who don’t bother to read the fine print. ![]()
Steve Jobs said good artists copy, great artists steal. Like how he stole many ideas from others it is a common practice on YT to steal the work of many hard working YTers especially when someone is very famous.
So, is it real or not? I’m very confused here. Doesn’t the other artist have to agree from their individual account before it can be tagged, especially since the revenue is shared?
The field in question is not a collaboration with Sapien Medicine, and is a creation of the person called Ygreck only. So it is NOT a real SM field.
Without acceptance from the captain’s side, how can he get Sapien into the collaboration
Hi there @Light1 !
Awww, that’s sweet. Thanks for the welcome ![]()
There is also a new album available on Sapien Medicine on Amazon (Quantum Resource Architecture).
Maybe a collaboration ?
The visual style of the album cover and the music fit well with the Sapien Medicine vibe.
I also thought the same thing, the audio image is very similar or fits well with Sapien’s, even so, it seems strange to me that the new album that appeared, but that one doesn’t look like a collaboration, only the name Sapien Medicine appears.








